110 Balanced Binary Tree – Easy
Problem:
Thoughts:
Solutions:
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) {
if (root == null) {
return true;
}
return height(root) > 0;
}
private int height(TreeNode node) {
if (node == null) {
return 0;
}
int left = height(node.left);
int right = height(node.right);
if (left < 0 || right < 0 || Math.abs(left - right) > 1) {
return -1;
}
return Math.max(left, right) + 1;
}
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