203 LeetCode Java: Remove Linked List Elements – Easy
Problem:
Remove all elements from a linked list of integers that have value val.
Example Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6 Return: 1 –> 2 –> 3 –> 4 –> 5
Thoughts;
This is a very simple linked list problem. Using a fakeHead is helping a lot for edge cases.
For many linked list problem, it’s always good practice to add a fakeHead in front in avoid null pointer problem in edge cases.
Solutions:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 /**
Definition for singly-linked list.
public class ListNode {
int val;
ListNode next;
ListNode(int x) { val = x; }
} */ public class Solution { public ListNode removeElements(ListNode head, int val) { ListNode fakeHead = new ListNode(-1); fakeHead.next = head;
ListNode parent = fakeHead; ListNode node = head; while (node != null){ if (node.val == val) parent.next = node.next; else parent = node; node = node.next; }//while return fakeHead.next;
} }
Updated: 12/31/2016
Improve logic.
```java
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode removeElements(ListNode head, int val) {
ListNode fakeHead = new ListNode(-1);
fakeHead.next = head;
ListNode node = fakeHead;
while (node.next != null) {
if (node.next.val == val) {
node.next = node.next.next;
}
else {
node = node.next;
}
}
return fakeHead.next;
}
}
```
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